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sql 中如何查询一个字段符合两个条件

你这中间有一个or 的关系,必须括起来 select m.create_time from msg m where (m.msg_txt like '%c-%' or m.msg_txt like '%e-%') and m.create_time like '2013-06%' order by m.create_time desc 另外一个问题是, 你这列到底是日期还是字符...

select 字段1,字段2,...字段n from 表名(如果有条件的话)where age=12 and name=“小名”(如果想排序的话) order by desc(asc)(如果想限制查询条数的话)limit=10 希望对你有帮助!

大数据查询跟字段是否有索引也有关系的 1、select * from test where a in ('x1','x2') and b in ('y1','y2') 不知道是不是要这样的

select * from otim where sheetid in(1,2,3) 结构化查询语言(Structured Query Language)简称SQL(发音:/ˈes kjuː ˈel/ "S-Q-L"),是一种特殊目的的编程语言,是一种数据库查询和程序设计语言,用于存取数据以及查询、更新和管...

sqlserver: select 发文单位+文号 as 发文单位文号 from table; oracle: select 发文单位||文号 as 发文单位文号 from table; select concat(发文单位,文号) as 发文单位文号 from table; mysql: select concat(发文单位,文号) as 发文单位文...

以下语句完美解决! SELECT id FROM dollar WHERE id in(SELECT id FROM dollar WHERE type NOT IN('a') GROUP BY id HAVING SUM([money])>=300) AND id in(SELECT id FROM dollar WHERE type IN('c','d') GROUP BY id HAVING SUM([money])

假如表1,表2分别为table1,table2,关联字段是id,那么 select t1.*, t2.* from table1 t1, table2 t2 where t1.id = t2.id and t1.字段 = A条件 and t2.字段 = B条件 左连接就是left join啊 select * from table1 t1 left join table2 t2 on t...

select sum(case when con1||con2='11' then count else 0 end) 三星笔记本, sum(case when con1||con2='12' then count else 0 end) 三星台式机, sum(case when con1||con2='22' then count else 0 end) 苹果笔记本, sum(case when con1||con2=...

首先,需要符合两个条件,即where a=b and c=d; 其次,需要合并重复的资料,即group by a ; 最后,只显示2条记录,即top 2; 整条sql就是: select top 2 * from table where a=b and c=d group by a; 上面是a字段有重复的情况,若多个字段有重...

1、用IN select * from b where id in (select id from a where 条件) 2、用JOIN select b.* from b inner join a on b.ID=a.ID where 条件 (如:where a.字段1=1)

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